Y=1/8x^2+2x-4

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Solution for Y=1/8x^2+2x-4 equation: 



=1/8Y^2+2Y-4

We move all terms to the left:

-(1/8Y^2+2Y-4)=0



Domain of the equation: 8Y^2+2Y-4)!=0

Y∈R



We get rid of parentheses

-1/8Y^2-2Y+4=0

We multiply all the terms by the denominator


-2Y*8Y^2+4*8Y^2-1=0

Wy multiply elements

-16Y^3+32Y^2-1=0

We do not support eYpression: Y^3

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